Population Size: 1000
q² (Homozygous Recessive Individuals Population): 0.612 or 61.2% of population
Directions:
1: Since they gave the value of q², I can find the value of the recessive allele frequency by square rooting q².
√.612=.782 or 78.2%
2: Now that I have q, I can find p (dominant allele frequency) by subtracting the q value from 1 because p+q=1.
1 - .782=.218 or 21.8%
3: With p I can find the homozygous dominant individual population p² by squaring p.
(.218)²=.048 or 4.8%
4: I can also find 2pq (heterozygotes) by multiplying p, q , and 2.
2(.782)(.218)=.34 or 34%
5: By multiplying p², q², and 2pq by the total population, 1,000, I can find the number of individuals of each genotype
q²- .612(1,000)=612
p²- .048(1,000)=48
2pq- .34(1,000)=340
6: By multiplying the population by 2 and the allele frequencies, p and q, I can find the number of genes of both dominant and recessive alleles.
q- 1,000(2)(.782)=1564
p- 1,000(2)(.218)=436
Answers:
q=.782
p=.218
q²=.612
p²=.048
2pq=.34
Homozygous Recessive Individuals:612
Homozygous Dominant Individuals: 48
Heterozygous Individuals: 340
Recessive Alleles: 1564
Dominant Alleles: 436
